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CAT 2020 Exam Shift 3 Solved Paper
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© examsnet.com
Question : 72
Total: 76
Two alcohol solutions,
A
and
B
, are mixed in the proportion
1
:
3
by volume. The volume of the mixture is then doubled by adding solution
A
such that the resulting mixture has
72
%
alcohol. If solution
A
has
60
%
alcohol, then the percentage of alcohol in solution
B
is
94
%
92
%
90
%
89
%
Validate
Solution:
Let the quantity of solutions
A
and
B
mixed initially be
p
and
3
p
respectively.
After an additional
4
p
of solution
A
is added
60
%
of
(
1
p
+
4
p
)
+
x
%
of
3
p
=
72
%
of
(
1
p
+
4
p
+
3
p
)
⇒
x
=
92
© examsnet.com
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