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CAT 2020 Exam Shift 3 Solved Paper
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© examsnet.com
Question : 74
Total: 76
A batsman played
n
+
2
innings and got out on all occasions. His average score in these
n
+
2
innings was 29 runs and he scored 38 and 15 runs in the last two innings. The batsman scored less than 38 runs in each of the first
n
innings. In these
n
innings, his average score was 30 runs and lowest score was
x
runs. The smallest possible value of
x
is
2
3
4
1
Validate
Solution:
Total score in
(
n
+
2
)
innings
=
29
×
(
n
+
2
)
The total score in
n
innings
=
29
(
n
+
2
)
−
38
−
15
=
29
n
+
5
=
30
n
⇒
n
=
5
Total score in 5 innings
=
30
×
5
=
150
=
37
×
4
+
2
© examsnet.com
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