A is the HCF of 3k+4k+5k for different values of k. For k=1, value is 12 For k=2, value is 50 For k=3, value is 216 HCF is 2. Therefore, A=2 4k+3(4k)+4k+2=4k(1+3)+4k+2=4k+1+4k+2=4k+1(1+4)=54k+1 HCF of the values is when k=1, i.e. 5×16=80 Therefore, B=80 A+B=82