Let the total work be 48 units. Let Amar do ′m′ work, Akbar do ′k′ work, and Anthony do ′n′ units of work in a month. Amar and Akbar complete the project in 12 months. Hence, in a month they do
48
12
=4units of work. m+k=4 Similarly, k+n=3, and m+n=2 Solving the three equations, we get m=
3
2
,k=
5
2
,n=
1
2.
Here, Amar works neither the fastest not the slowest, and he does 1.5units of work in a month. Hence, to complete the work, he would take