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CAT Exam Model Paper 1 with solutions for free online practice
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© examsnet.com
Question : 80
Total: 100
If the string is wound on the exterior four walls of a cube of side a cm starting at point C and ending at point D exactly above C, making equally spaced 4 turns. The side of the cube is [Total length of string = 8n cm]
a
=
2
n
√
255
a
=
(
n
)
2
16
a
=
8
n
√
257
a
=
2
√
15
n
Validate
Solution:
(c) Given, total length of string = 8n cm
Length of string required for 1 turn (or round)
=
8
n
4
=
2
n
but
2
n
=
√
(
a
4
)
2
+
(
4
a
)
2
⇒
a
=
8
n
√
257
where, a is the side of cube.
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