(c) Let the total quantity of mixture be ‘Z’ kg Let the total quantity of Dia mixture be 600 kg. This 6% of K is obtained only from Dia, KU+KD=RM ⇒0+
10
100
×600=
6
100
×Z ⇒
60×100
6
=Z ⇒ Z = 1000 kg
NU+ND=NM⇒NU+120=260 ⇒NU=260−120=140‌kg and PU+PD=PM ⇒PU+420=680⇒PU=680−420=260 kg U, D, M → Urea, Dia and mixture ∴ Ratio of N : P = 7 : 13 ⇒ 35: 65