) ⇒P=(1+a)(1+a2)(1+a4)... ⇒(1−a)P=(1−a)(1+a)(1+a2)(1+a4)(1+a8)... ⇒(1−a)P=(1−a2)(1+a2)(1+a4)(1+a8)... ⇒(1−a)P=(1−a4)(1+a4)(1+a8)... Since a is negative, as the power of a increases the value would keep getting closer to 0 So RHS = 1 ⇒ (1 - a )P = 1 P=