⇒ x+3y=7 ...(i) On taking first two terms, 8(5x−7y+10)=3x+2y+1 37x−58y+79=0 ....(ii) From equation (i), on putting the value of x in equation (ii), we get 37(7−3y)−58y+79=0 ⇒ 259−111y−58y+79=0 ⇒ 169y=338 ⇒ y=2 From equation (i), x=7−3(2)=1 ∴ x+y=1+2=3