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CDS Model Paper 5 Mathematics
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© examsnet.com
Question : 15
Total: 100
A journey of
192
km
between two cities takes two hours less by a fast train than by a slow train. If the average speed of the slow train is
16
km
∕
h
less than that of the fast train, then the average speed of the fast train is :
36
km
∕
h
64
km
∕
h
32
km
∕
h
48
km
∕
h
Validate
Solution:
Let the speed of the faster train be
x
km
∕
h
.
⇒ speed of the slower train
=
(
x
−
16
)
km
∕
h
Now,
192
x
=
192
x
−
16
−
2
or
x
=
48
km
∕
h
© examsnet.com
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