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CGPET 2013 Solved Paper
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© examsnet.com
Question : 28
Total: 150
The electric potential at a point in free space due to change
Q
coulomb is
Q
×
10
11
V
. The electric field at that point is
4
π
ε
0
Q
×
10
20
V
∕
m
12
π
ε
0
Q
×
10
22
V
∕
m
4
π
ε
0
Q
×
10
22
V
∕
m
12
π
ε
0
Q
×
10
20
V
∕
m
Validate
Solution:
Given,
V
=
KQ
r
=
Q
×
10
11
V
⇒
r
=
KQ
Q
×
10
11
=
K
10
11
m
The electric field at that point,
E
=
KQ
r
2
=
KQ
(
K
∕
10
11
)
2
V
∕
m
=
KQ
K
2
×
10
22
V
∕
m
=
4
π
ε
0
×
Q
×
10
22
V
∕
m
© examsnet.com
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