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CGPET 2015 Solved Paper
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Section:
Physics
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© examsnet.com
Question : 25
Total: 150
If one mole of a monoatomic gas
(
γ
=
‌
5
3
)
is mixed with one mole diatomic gas
(
γ
=
‌
7
5
)
, the value of
γ
for the mixture is
1.40
1.50
1.53
3.07
Validate
Solution:
For monoatomic gas,
γ
1
=
C
p
1
C
v
1
=
5
3
and
C
p
1
−
C
v
1
=
R
this gives
C
p
1
=
5
2
R
‌
and
‌
C
v
1
=
3
2
R
For diatomic gas,
γ
2
=
C
p
2
C
v
2
=
7
5
and
C
p
2
−
C
v
2
=
R
⇒
C
p
2
=
7
2
R
and
C
v
2
=
5
2
R
Now, we can write,
γ
mix
=
n
1
C
p
1
+
n
2
C
p
2
n
1
C
v
1
+
n
2
C
v
2
=
C
p
1
+
C
p
2
C
v
1
+
C
v
2
=
5
2
R
+
7
2
R
3
2
R
+
5
2
R
=
12
8
=
3
2
=
1.5
© examsnet.com
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