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CGPET 2015 Solved Paper
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© examsnet.com
Question : 58
Total: 150
Vapour pressure of a solution at
100
∘
C
having
3.42
g
of cane sugar in
180
g
water is
759.2
mm
760
mm
740
mm
748.5
mm
Validate
Solution:
According to Raoult's law, relative lowering in vapour pressure
p
°
A
−
p
S
p
°
A
=
n
S
n
A
+
n
B
n
A
=
180
18
=
10
and
n
S
=
3.42
342
=
0.01
Here, atmospheric pressure
p
°
A
= 760mm of Hg
∴
760
−
p
S
760
p
s
=
0.01
10
+
0.01
=
0.01
10.01
=
0.00099
or,
760
−
p
S
=
0.75924
or,
p
S
=
760
−
0.75924
=
759.24076
mm
© examsnet.com
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