Thermal resistance of the combination are RI=R1+R2=K+1AI+K2AI=AI(K11+K21)R1=AI(K1K2K2+K1)RII (Parallel combination) RII=R1+R2R1R2AI(K1K2K1+K2)K1AI×K2AIA(K1+K2)I So, the heat flow rates are Case I I=t1Q=AI(K1K2K1+K2)ΔQ .....(i) t1Q=AI(3K23K)ΔQ=AI(2K3)ΔQCase II t2Q=AI(K1+K21)ΔQ=AI(3K1)ΔQ .....(ii) Divide Eq. (i) and Eq. (ii), we get t2Qt1Q=AI(3K1)ΔQAI(2K3)ΔQ=92t1t2=92t=9×92=2s