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CGPET 2017 Solved Paper
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© examsnet.com
Question : 32
Total: 150
The equation of the stationary wave along a stretched string is given by
y
=
5
sin
π
x
3
cos
40
π
t
where
x
and
y
are in
c
m
and
t
in
s
. The separation between two adjacent nodes is
1.5
c
m
3
c
m
4
c
m
6
c
m
Validate
Solution:
The equation of stationary wave in a stretched string
y
=
5
sin
π
x
3
cos
4
π
t
........(i)
Comparing this equation with the standard equation of stationary waves
y
=
2
A
sin
k
x
cos
ω
t
........(ii)
Comparison of given equation of stationary wave
k
=
π
3
ω
=
40
π
=
2
π
v
v
=
20
c
∕
s
e
c
v
=
ω
k
=
40
π
π
3
=
120
c
m
∕
s
v
=
v
λ
⇒
λ
=
120
20
=
6
c
m
The distance between two adjacent nodes
=
λ
2
=
6
2
=
3
c
m
© examsnet.com
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