Given differential equation xdxdy=y−xtan(xy) ⇒ dxdy=xy−tan(xy) ........(i) which is homogeneous differential equation. Now, put xy=v⇒y=vx⇒dxdy=v+xdxdv .........(ii) From Eqs. (i) and (ii), we get ⇒v+xdxdv=v−tanv⇒xdxdv=−tanv⇒tanvdv=−xdx⇒cotvdv=−x1dx On integrating both the sides, we get log(sinv)=−logx+logC⇒log(sinxy)+logx=logC⇒log(x⋅sinxy)=logC⇒x⋅sin(xy)=C