On bombardment of 11H proton, an α -particle will comes out as follows: 816O+11H→713N+24HeSum of mass number Reactant side =16+1=17 Product side =13+4=17Sum of atomic number Reactant side =8+1=9 Product side =7+2=9 As bombarding particle, 11H is can be written as proton (p) and ejecting particle can be written as (α). The whole reaction can be summarised as follows: 816O(p,α),13N Hence, (a) is the correct option.