Let r=xi^+yj^+zk^(r⋅i^)=(xi^+yj^+zk^)⋅i^(r⋅i^)=x⇒(r⋅i^)2=x2 .......(i) (r⋅j^)=(xi^+yj^+zk^)⋅j^(r⋅j^)=y⇒(r⋅j^)2=y2 ...........(ii) And (r⋅k^)=(x⋅i^+y⋅j^+z⋅k^)⋅k^(r⋅k^)=z⇒(r⋅k^)2=z2 .........(iii) Now, (r⋅i^)2+(r⋅j^)2+(r⋅k^)2 Put the value of Eqs.(i), (ii) and (iii), we get =x2+y2+z2=r2