)=4y−2x−2 ∴ Pair of tangent from P(1,4) is (y2−4x)(12)=(4y−2x−2)2 ⇒ 12(y2−4x)=4(2y−x−1)2 ⇒ 3(y2−4x)=4y2+x2+1−4xy+2x−4y ⇒ 3y2−12x=4y2+x2+1−4xy+2x−4y ⇒ x2+y2−4xy+14x−4y+1=0.......(i) ∴ a=1,b=1,h=−2,g=7,f=−2,c=1 Let θ be the angle between pair of tangents represented by eq. (i) ∴ tanθ=|