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CGPET 2022 Solved Paper
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© examsnet.com
Question : 2
Total: 150
A rod of length
L
and mass
M
is bent into form of a semi-circular ring (as shown in figure). The moment of inertia about
X
Y
-axis is
M
L
2
2
π
2
M
L
2
π
2
M
L
2
4
π
2
2
M
L
2
π
2
Validate
Solution:
Moment of inertia of a semi-circular ring (using standard results) is
I
=
1
2
M
R
2
.
.
.
(
i
)
As rod of length
L
is bent into semi-circular ring. Then,
π
R
=
L
or
R
=
L
π
So, moment of inertia is given by
I
=
1
2
M
⋅
(
L
π
)
2
or
I
=
M
L
2
2
π
2
© examsnet.com
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