In SHM , velocity, v=ω√A2−y2 v2=ω2(A2−y2)...(i) and acceleration, a=−ω2y ⇒a2=ω4y2...(ii) From Eqs.(i)‌and(ii) , we have ⇒v2=ω2A2−ω2y2 ⇒v2=ω2A2−ω2a2 ⇒v2=−ω2a2+ω2A2 Comparing with y=mx+c Above equation is a straight line with negative slope and positive intercept.