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CMAT 2013 Solved Question Paper
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© examsnet.com
Question : 14
Total: 100
Two pipes A and B can fill a cistern in 15 h and 10 h respectively. A tap C can empty the full cistern in 30 h. All the three taps were open for 2 h, when it was remembered that emptying tap had been left open. It was then closed. How many hours more would it take for the cistern to be filled?
8 h 30 min
1.2 h
6 h 24 min
5 h 35 min
Validate
Solution:
(c) Time taken by pipes A and B to fill the whole tank =
100
16.66
Capacity filled in 2 h by pipes A, B and C = 2 x 13.33 = 26 66%
Remaining capacity = 73.33%
This remaining capacity can be filled by A and B =
73.33
16.66
=
4
2
5
h
So, the total time required = 2 + 4
2
5
h = 6 h 24 min
Thus, in this case 24 min extra are required.
© examsnet.com
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