Given, x = OA = 4 AB is the diagonal of square, so it must be 4 x2 = 8 As diagonal of square = √2 a, where a is the side ofsquare. Therefore, √2 a =8 ⇒a =
8
√2
=4√2 Also, diameter of circle = side of square ⇒ d = 4√2 ⇒ perimeter of circle = πd = 4√2 π