COMEDK Exam 2018 Solved Paper

We know that, in series combination of capacitors, net potential difference is equal to sum of the individual potential difference of each capacitor
‌ i.e., ‌‌‌V‌=V1+V2+V3.......‌‌[V1=V2=V3=200V]
⇒‌‌600‌=n×200
⇒‌‌n‌=3
So, there should be 3 capacitors in series to obtain the required potential difference. The equivalent capacitance of 3 capacitors in series is given as
‌‌

1

Ceq

=‌

1

6

+‌

1

6

+‌

1

6

=‌

3

6

=‌

1

2

‌⇒‌‌Ceq=2µF
Now, we require 18µF capacitance for this, we need 9 number of such capacitors in parallel.
∴ Total number of capacitors (condensers)
=9×3=27