Concept:A number is divisible by 2 if its last digit is even (0, 2, 4, 6, 8).
Divisibility by 3 requires the sum of digits to be divisible by 3.
Divisibility by 11 requires the difference between sum of digits at even and odd places to be 0 or divisible by 11.
Explanation:Check each number step by step.
For 8448:
Last digit 8 → divisible by 2.
Sum of digits: 8+4+4+8 = 24 → divisible by 3.
Even place digits: positions 2 and 4 give 4+8 = 12.
Odd place digits: positions 1 and 3 give 8+4 = 12.
Difference = 12 – 12 = 0 → divisible by 11.
So 8448 is divisible by 2, 3, and 11.
For 9812:
Last digit 2 → divisible by 2.
Sum of digits: 9+8+1+2 = 20 → not divisible by 3.
Fails the condition. No need to check further.
For 9126:
Last digit 6 → divisible by 2.
Sum of digits: 9+1+2+6 = 18 → divisible by 3.
Even place digits: 1+6 = 7.
Odd place digits: 9+2 = 11.
Difference = 11 – 7 = 4 → not divisible by 11.
Fails the condition.
For 9636:
Last digit 6 → divisible by 2.
Sum of digits: 9+6+3+6 = 24 → divisible by 3.
Even place digits: 6+6 = 12.
Odd place digits: 9+3 = 12.
Difference = 12 – 12 = 0 → divisible by 11.
So 9636 is divisible by 2, 3, and 11.
Only 8448 and 9636 satisfy all three conditions.
Answer:A and D → option C.