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EAMCET Engineering 2001 Solved Paper
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© examsnet.com
Question : 10
Total: 200
Light waves producing interference have their amplitudes in the ratio
3
:
2
. The intensity ratio of maximum and minimum of interference fringes is
36
:
1
9
:
4
25
:
1
6
:
4
Validate
Solution:
Ratio of amplitudes,
a
1
a
2
=
3
2
a
1
=
3
k
,
a
2
=
2
k
I
max
I
min
=
(
a
1
+
a
2
)
2
(
a
1
−
a
2
)
2
=
(
3
k
+
2
k
)
2
(
3
k
−
2
k
)
2
=
25
1
I
max
:
I
min
=
25
:
1
© examsnet.com
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