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EAMCET Engineering 2001 Solved Paper
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© examsnet.com
Question : 148
Total: 200
If
u
=
e
x
2
−
y
2
, then
x
u
x
=
y
u
y
y
u
x
=
x
u
y
y
u
x
+
x
u
y
=
0
x
2
u
y
+
y
2
u
x
=
0
Validate
Solution:
Given that,
u
=
e
x
2
−
y
2
On differentiating partially w.r.t.
x
.
u
x
=
e
x
2
−
y
2
(
2
x
)
On differentiating partially w.r.t.
y
.
u
y
=
e
x
2
−
y
2
(
−
2
y
)
y
u
x
=
e
x
2
−
y
2
2
x
y
. . . (i)
x
u
y
=
e
x
2
−
y
2
(
−
2
x
y
)
. . . (ii)
On adding Eqs. (i) and (ii)
y
u
x
+
x
u
y
=
0
© examsnet.com
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