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EAMCET Engineering 2001 Solved Paper
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© examsnet.com
Question : 3
Total: 200
Two electric charges of
9
µ
C
and
−
3
µ
C
are placed
0.16
m
apart in air. There will be a point '
P
', at which electric potential is zero on the line joining two charges and in between them. The distance of
P
from
9
µ
C
is
0.14
m
0.12
m
0.08
m
0.06
m
Validate
Solution:
q
1
=
9
µ
C
,
q
2
=
−
3
µ
C
,
r
=
0.16
m
Potential at point '
P
',
V
1
+
V
2
=
0
or
V
1
=
−
V
2
1
4
π
ε
0
q
1
r
1
=
−
1
4
π
ε
0
q
2
r
2
9
x
=
−
(
−
3
)
(
0.16
−
x
)
⇒
3
(
0.16
−
x
)
=
x
0.48
−
3
x
=
x
4
x
=
0.48
⇒
x
=
0.12
m
© examsnet.com
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