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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 120
Total: 200
If the pair of straight lines
x
y
−
x
−
y
+
1
=
0
and the line
a
x
+
2
y
−
3
a
=
0
are concurrent, then
a
is equal to
0
1
-1
3
Validate
Solution:
We have,
and
x
y
−
x
−
y
+
1
=
0
. . . (i)
a
x
+
2
y
−
3
a
=
0
. . . (ii)
On comparing Eqs. (i) with,
a
x
2
+
2
h
x
y
+
b
y
2
+
2
g
x
+
2
f
y
+
c
=
0
, we get
a
=
0
,
b
=
0
,
h
=
1
2
,
g
=
−
1
2
,
f
=
−
1
2
,
c
=
1
The point of concurrent is
(
h
f
−
b
g
a
b
−
h
2
g
h
−
a
f
a
b
−
h
2
)
=
(
1
2
(
−
1
2
)
−
0
0
−
(
1
2
)
2
,
(
−
1
2
)
(
1
2
)
−
0
0
−
(
1
2
)
2
)
=
(
1
,
1
)
This point lies on equation (ii), then
a
+
2
−
3
a
=
0
⇒
2
a
=
2
⇒
a
=
1
© examsnet.com
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