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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 26
Total: 200
If
λ
0
is the de-Broglie wavelength for a proton accelerated through a potential difference of
100
V
, the de-Broglie wavelength for
α
-particle accelerated through the same potential difference is
2
√
2
λ
0
λ
0
2
λ
0
2
√
2
λ
0
√
2
Validate
Solution:
V
=
100
volt
Given,
λ
0
=
de-Broglie wavelength of proton
∴
λ
0
=
h
√
2
m
p
q
p
V
de-Broglie wavelength of
α
-particle
λ
=
h
√
2
m
α
q
α
V
m
α
=
4
m
p
(Mass of
α
-particle is four times of proton)
q
α
=
2
q
p
(Charge of
α
-particle is twice of proton)
λ
λ
=
h
√
2
(
4
m
p
)
(
2
q
p
)
V
=
1
√
8
h
√
2
m
p
q
p
V
=
λ
0
√
8
=
λ
0
2
√
2
© examsnet.com
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