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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 39
Total: 200
Particles of masses
m
,
2
m
,
3
m
,
.
.
.
n
m
grams are placed on the same line at distance
l
,
2
l
,
3
l
.
.
.
n
l
cm
from a fixed point. The distance of centre of mass of the particles from the fixed point in centimetre is
(
2
n
+
1
)
l
3
l
n
+
1
n
(
n
2
+
1
)
l
2
2
l
n
(
n
2
+
1
)
Validate
Solution:
Distance of centre of mass
x
c
m
=
m
1
x
1
+
m
2
x
2
+
.
.
.
m
n
x
n
m
1
+
m
2
+
.
.
.
m
n
=
m
l
+
2
m
2
l
+
.
.
.
n
m
×
n
l
m
+
2
m
+
3
m
+
.
.
.
n
m
=
m
l
(
1
+
4
+
9
+
.
.
.
n
2
)
m
(
1
+
2
+
3
+
.
.
.
n
)
1
+
4
+
9
+
.
.
.
n
2
=
Σ
n
2
=
n
(
n
+
1
)
(
2
n
+
1
)
6
1
+
2
+
3
+
.
.
.
n
=
Σ
n
=
n
(
n
+
1
)
2
∴
x
c
m
=
ln
(
n
+
1
)
(
2
n
+
1
)
6
n
(
n
+
1
)
2
=
l
(
2
n
+
1
)
3
© examsnet.com
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