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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 5
Total: 200
If the displacement
(
x
)
and velocity
(
v
)
of a particle executing simple harmonic motion are related through the expression
4
v
2
=
25
−
x
2
, then time period is
π
2
π
4
π
6
π
Validate
Solution:
4
v
2
=
25
−
x
2
Differentiating both the side
4
(
2
v
)
d
v
d
t
=
0
−
2
x
d
x
d
t
d
v
d
t
=
A
(acceleration)
d
x
d
t
=
v
(velocity)
∴
8
v
×
A
=
−
2
x
4
A
=
−
x
x
A
=
−
1
4
⇒
Displacement
Acceleration
=
1
4
Time period
T
=
2
π
√
displacement
acceleration
=
2
π
√
1
4
=
2
π
×
1
2
=
π
s
e
c
© examsnet.com
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