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EAMCET Engineering 2002 Solved Paper
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© examsnet.com
Question : 56
Total: 200
4
g
of an ideal gas occupies
5.6035
L
of volume at
546
K
and 2 atmosphere pressure. What is its molecular weight?
4
16
32
64
Validate
Solution:
W
=
4
g
,
V
=
5.6035
L
,
T
=
546
K
,
P
=
2
atm
M
w
=
R
T
P
V
(
∵
n
=
W
M
)
M
4
=
0.0821
×
546
2
×
5.6035
∴
M
=
16
© examsnet.com
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