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EAMCET Engineering 2003 Solved Paper
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© examsnet.com
Question : 108
Total: 160
The eccentricity of the ellipse
9
x
2
+
5
y
2
−
18
x
−
20
y
−
16
=
0
, is :
1
2
2
3
3
2
2
Validate
Solution:
Equation of ellipse is
9
x
2
+
5
y
2
−
18
x
−
20
y
−
16
=
0
⇒
9
(
x
2
−
2
x
)
+
5
(
y
2
−
4
y
)
=
16
⇒
9
(
x
2
−
2
x
+
1
)
+
5
(
y
2
−
4
y
+
4
)
=
16
+
9
+
20
⇒
9
(
x
−
1
)
2
+
5
(
y
−
2
)
2
=
45
⇒
(
x
−
1
)
2
5
+
(
y
−
2
)
2
9
=
1
Here
a
2
=
5
,
b
2
=
9
eccentricity,
e
=
√
1
−
a
2
b
2
=
√
1
−
5
9
=
2
3
© examsnet.com
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