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EAMCET Engineering 2003 Solved Paper
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© examsnet.com
Question : 13
Total: 160
A large tank filled with water to a height
h
is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from
h
to
h
∕
2
and
h
∕
2
to zero is
√
2
1
√
2
√
2
−
1
1
√
2
−
1
Validate
Solution:
Time taken,
t
=
√
2
h
g
Time taken for the level of water to fall from
h
to
h
∕
2
to 0 ,
t
1
=
√
2
g
(
√
h
1
−
√
h
2
)
=
√
2
g
(
√
h
−
√
h
2
)
=
√
2
h
g
(
1
−
1
√
2
)
Similarly, time taken for the level of water to fall from
h
∕
2
to 0.
t
2
=
√
2
g
(
√
h
2
−
0
)
⇒
t
2
=
√
2
h
g
⋅
1
√
2
∴
t
1
t
2
=
√
2
h
g
(
1
−
1
√
2
)
√
2
h
g
1
√
2
=
(
√
2
−
1
√
2
)
1
∕
√
2
=
√
2
−
1
© examsnet.com
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