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EAMCET Engineering 2004 Solved Paper
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© examsnet.com
Question : 5
Total: 160
A block of mass
2
kg
is initially at rest on a horizontal frictionless surface. A horizontal force
→
F
=
(
9
−
x
2
)
^
i
newtons acts on it, when the block is at
x
=
0
. The maximum kinetic energy of the block between
x
=
0
and
x
=
3
m
in joule is
24
20
18
15
Validate
Solution:
KE
=
∫
F
dx
KE
=
x
=
3
∫
x
=
0
(
9
−
x
2
)
dx
=
9
x
=
3
∫
x
=
0
dx
−
x
=
3
∫
x
=
0
x
2
dx
=
9
[
x
]
0
3
−
[
x
3
3
]
0
3
=
27
−
9
=
18
J
.
© examsnet.com
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