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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 141
Total: 160
f
(
x
)
=
e
x
s
i
n
x
, then
f
(
6
)
(
x
)
is equal to :
e
6
x
s
i
n
6
x
−
8
e
x
cos
x
8
e
x
s
i
n
x
8
e
x
cos
x
Validate
Solution:
f
(
x
)
=
e
x
s
i
n
x
∴
f
′
(
x
)
=
e
x
cos
x
+
s
i
n
x
e
x
⇒
f
′
′
(
x
)
=
e
x
cos
x
−
e
x
s
i
n
x
+
e
x
s
i
n
x
+
e
x
cos
x
=
2
e
x
cos
x
Now,
f
′
′
′
(
x
)
=
−
2
e
x
s
i
n
x
+
2
e
x
cos
x
and
f
i
v
(
x
)
=
−
2
e
x
s
i
n
x
−
2
e
x
cos
x
+
2
e
x
cos
x
−
2
e
x
s
i
n
x
=
−
4
e
x
s
i
n
x
f
v
(
x
)
=
−
4
e
x
cos
x
−
4
e
x
s
i
n
x
f
v
i
(
x
)
=
−
4
e
x
cos
x
+
4
e
x
s
i
n
x
+
4
e
x
s
i
n
x
−
4
e
x
cos
x
=
−
8
e
x
cos
x
© examsnet.com
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