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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 157
Total: 160
1
∫
−
1
cos
h
x
1
+
e
2
x
dx
is equal to :
0
1
e
2
−
1
2
e
e
2
+
2
2
e
Validate
Solution:
I
=
1
∫
−
1
cosh
x
1
+
e
2
x
dx
1
∫
−
1
e
x
+
e
−
x
2
(
1
+
e
2
x
)
dx
(
∵
cosh
x
=
e
x
+
e
−
x
2
)
1
2
1
∫
−
1
1
+
e
2
x
(
1
+
e
2
x
)
e
x
⋅
dx
1
2
1
∫
−
1
e
−
x
dx
=
−
1
2
[
e
−
x
]
−
1
1
=
−
1
2
(
e
−
1
−
e
1
)
=
e
2
−
1
2
e
© examsnet.com
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