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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 28
Total: 160
Two short magnets
A
B
and
C
D
are in the
X
−
Y
plane and are parallel to
X
-axis and co-ordinates of their centres respectively are
(
0
,
2
)
and
(
2
,
0
)
. Line joining the north-south poles of
C
D
is opposite to that of
A
B
and lies along the positive
X
-axis. The resultant field induction due to
A
B
and
C
D
at a point
P
(
2
,
2
)
is
100
×
10
−
7
T
. When the poles of the magnet
C
D
are reversed, the resultant field induction is
50
×
10
−
7
T
. The value of magnetic moments of
A
B
and
C
D
(in
Am
2
) are :
300
;
200
600
;
400
200
;
100
300
;
150
Validate
Solution:
As shown in figure
B
=
B
1
+
B
2
=
µ
0
4
π
(
2
M
1
r
1
3
+
M
2
r
2
3
)
100
×
10
−
7
=
10
−
7
(
2
M
1
8
+
M
2
8
)
⇒
2
M
1
+
M
2
=
800
. . . (i)
If the poles of the magnet
C
D
are reversed, then
50
×
10
−
7
=
10
−
7
(
2
M
1
8
−
M
2
8
)
⇒
2
M
1
−
M
2
=
400
. . . (ii)
Solving Eqs. (i) and (ii), we obtain
M
1
=
300
Am
2
,
M
2
=
200
Am
2
© examsnet.com
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