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EAMCET Engineering 2006 Solved Paper
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© examsnet.com
Question : 3
Total: 160
A body is projected from the earth at angle
30
∘
with the horizontal with some initial velocity. If its range is
20
m
, the maximum height reached by it is : (in metres)
5
√
3
5
√
3
10
√
3
10
√
3
Validate
Solution:
R
=
u
2
s
i
n
2
θ
g
∴
20
=
u
2
s
i
n
(
2
×
30
∘
)
g
⇒
u
2
g
=
20
s
i
n
60
∘
=
20
√
3
×
2
=
40
√
3
Now,
H
=
u
2
s
i
n
2
θ
2
g
=
40
√
3
×
s
i
n
2
30
∘
2
=
40
√
3
×
(
1
2
)
2
2
=
5
√
3
m
© examsnet.com
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