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EAMCET Engineering 2007 Solved Paper
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© examsnet.com
Question : 22
Total: 160
A segment of wire vibrates with a fundamental frequency of
450
Hz
under a tension of
9
kg
wt. Then tension at which the fundamental frequency of the same wire becomes
900
Hz
is
36
kg
-wt
27
kg
−
wt
18
kg
-wt
72
kg
-wt
Validate
Solution:
Fundamental frequency of wire
f
=
1
2
π
√
T
m
or
f
∝
√
T
or
f
2
f
1
=
√
T
2
T
1
or
900
450
=
√
T
2
9
or
T
2
=
4
×
9
=
36
kg
−
wt
© examsnet.com
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