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EAMCET Engineering 2008 Solved Paper
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© examsnet.com
Question : 107
Total: 160
If
α
+
β
+
γ
=
2
θ
, then
cos
θ
+
cos
(
θ
−
α
)
+
cos
(
θ
−
β
)
+
cos
(
θ
−
γ
)
is equal to
4
s
i
n
α
2
⋅
cos
β
2
⋅
s
i
n
γ
2
4
cos
α
2
⋅
cos
β
2
⋅
cos
γ
2
4
s
i
n
α
2
⋅
s
i
n
β
2
⋅
s
i
n
γ
2
4
s
i
n
α
⋅
s
i
n
β
⋅
s
i
n
γ
Validate
Solution:
Now,
cos
(
θ
−
α
)
+
cos
(
θ
−
β
)
+
cos
θ
+
cos
(
θ
−
γ
)
=
2
cos
(
θ
−
(
α
+
β
2
)
)
cos
(
β
−
α
2
)
+
2
cos
(
γ
2
)
cos
(
θ
−
γ
2
)
=
2
cos
(
γ
2
)
cos
(
β
−
α
2
)
+
2
cos
(
γ
2
)
cos
(
α
+
β
2
)
=
2
cos
(
γ
2
)
[
cos
(
β
−
α
2
)
+
cos
(
α
+
β
2
)
]
=
2
cos
(
γ
2
)
2
cos
α
2
cos
β
2
=
4
cos
α
2
cos
β
2
cos
γ
2
© examsnet.com
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