Given that, f(x)=|x| and g(x)=[x−3] For ‌‌−‌
8
5
<x<‌
8
5
,0≤f(x)<‌
8
5
Now, for ‌‌0≤f(x)<1, g(f(x))‌=[f(x)−3] ‌=−3[∵−3≤f(x)−3<−2] Again, for 1≤f(x)<1.6 g(f(x))=−2 [∵−2≤f(x)−3<−1.4] Hence, required set is {−3,−2}.