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EAMCET Engineering 2009 Solved Paper
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© examsnet.com
Question : 21
Total: 160
In Young's double slit experiment, the
10
th
maximum of wavelength
λ
1
is at a distance of
y
1
from the central maximum. When the wavelength of the source is changed to
λ
2
,
5
th
maximum is at a distance of
y
2
from its central maximum. The ratio
(
y
1
y
2
)
is
2
λ
1
λ
2
2
λ
2
λ
1
λ
1
2
λ
2
λ
2
2
λ
1
Validate
Solution:
Position fringe from central maxima
y
1
=
n
λ
1
D
d
Given,
n
=
10
∴
y
1
=
10
λ
1
D
d
. . . (i)
For second source
y
2
=
5
λ
2
D
d
∴
10
λ
1
D
d
. . . (ii)
⇒
y
1
y
2
=
5
λ
2
D
d
y
1
y
2
=
2
λ
1
λ
2
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