Given,(x−a)(x−a−1)+(x−a−1)(x−a−2)+(x−a)(x−a−2)=0Let x−a=t, thent(t−1)+(t−1)(t−2)+t(t−2)=0⇒t2−t+t2−3t+2+t2−2t=0⇒3t2−6t+2=0⇒t=2(3)6±36−24​​=2(3)6±23​​⇒x−a=33±3​​⇒x=a+33±3​​Hence, x is real and distinct.