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EAMCET Engineering 2010 Solved Paper
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© examsnet.com
Question : 17
Total: 160
A pair of perpendicular lines passes through the origin and also through the points of intersection of the curve
x
2
+
y
2
=
4
with
x
+
y
=
a
, where
a
>
0
. Then
a
is equal to
2
3
4
5
Validate
Solution:
The intersection point of the curve
x
2
+
y
2
=
4
with
x
+
y
=
a
, where
(
a
>
0
)
x
2
+
(
a
−
x
)
2
=
4
x
2
+
a
2
+
x
2
−
2
a
x
=
4
2
x
2
−
2
a
x
+
(
a
2
−
4
)
=
0
x
2
−
a
x
+
(
a
2
2
−
2
)
=
0
x
=
+
a
±
√
a
2
−
4
(
a
2
2
−
2
)
2
x
=
a
±
√
a
2
−
2
a
2
+
8
2
=
a
±
√
8
−
a
2
2
Since, here the point of intersection should be real number, iff
8
−
a
2
≥
0
ie,
a
2
≤
8
,
a
≤
2
√
2
a
≤
2.82
Hence, the value is
a
=
2
according to option.
© examsnet.com
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