(√3+i)7+(√3−i)7 Let ‌‌√3+i=z z=(√3+i)=r(cos‌θ+isin‌θ) Then, ‌‌r‌cos‌θ=√3 . . . (i) rsin‌θ=1 . . . (ii) Eq. (i) + Eq. (ii), we get ‌r2(sin‌2θ+cos2θ)=3+1 ⇒r2=4 ⇒r=2 Eq. (ii) ÷ Eq. (i), we get ‌⇒‌‌tan‌θ=‌