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EAMCET Engineering 2010 Solved Paper
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© examsnet.com
Question : 94
Total: 160
A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each one is equal to 3/4th the angle of prism. The angle of deviation is
45
∘
39
∘
20
∘
30
∘
Validate
Solution:
Relation among the
(
i
)
,
(
e
)
,
(
A
)
and
(
δ
)
r
i
+
e
=
A
+
δ
3
4
×
60
∘
+
3
4
×
60
∘
=
60
∘
+
δ
or
45
∘
+
45
∘
=
60
∘
+
δ
or
δ
=
30
∘
where,
i
=
angle of incidence
e
=
angle of emergence
A
=
angle of prism
δ
=
angle of deviation
© examsnet.com
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