Test Index

Equations

© examsnet.com

Question : 10 of 39

Marks: +1, -0

Find the value of

m

if one of root is

-\frac{3}{2}

of the equation

x^{2}+x-m=0

1
0
$\frac{3}{4}$
-2

Solution:

Concept:

If a value is a root of an equation, substituting it into the equation satisfies the equation.

Explanation:

Given equation:

x^{2}+x-m=0

.

One root is

-\frac{3}{2}

.

Substitute

x = -\frac{3}{2}

into the equation:

\left(-\frac{3}{2}\right)^{2} + \left(-\frac{3}{2}\right) - m = 0

\frac{9}{4} - \frac{3}{2} - m = 0

Convert

\frac{3}{2}

to

\frac{6}{4}

:

\frac{9}{4} - \frac{6}{4} - m = 0

\frac{3}{4} - m = 0

Thus,

m = \frac{3}{4}

.

Answer:

m = \frac{3}{4}

© examsnet.com

Go to Question:

Prev Question

Next Question