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GATE Civil Engineering (CE) 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 43 of 65
Marks:
+1
,
-0
A
3
m
×
3
m
3 \text{ m} \times 3 \text{ m}
3
m
×
3
m
square precast reinforced concrete segments to be installed by pushing them through an existing railway embankment for making an underpass as shown in the figure. A reaction arrangement using precast PCC blocks placed on the ground is to be made for the jacks.
At each stage, the jacks are required to apply a force of
1875
kN
1875 \text{ kN}
1875
kN
to push the segment. The jacks will react against the rigid steel plate placed against the reaction arrangement. The footprint area of reaction arrangement on natural ground are:
c
=
17
kPa
;
φ
=
2
5
∘
c=17 \text{ kPa} ; \varphi=25^{\circ}
c
=
17
kPa
;
φ
=
2
5
∘
and
γ
=
18
kN/m
3
\gamma=18 \text{ kN/m}^3
γ
=
18
kN/m
3
. Assuming that the reaction arrangement has rough interface and has the same properties that of soil, the factor of safety (round off to 1 decimal place) against shear failure is
Your Answer:
Validate
Solution:
FOS against shear failure
=
Strength
Applied load
=
(
c
+
σ
tan
φ
)
A
P
= \frac{\text{ Strength }}{\text{ Applied load }} = \frac{(c+\sigma \tan \varphi) A}{P}
=
Applied load
Strength
=
P
(
c
+
σ
t
a
n
φ
)
A
σ
=
N
A
=
4
kN/m
2
×
37.5
m
2
×
7.5
m
37.5
m
2
\sigma = \frac{N}{A} = \frac{4 \text{ kN/m}^2 \times 37.5 \text{ m}^2 \times 7.5 \text{ m}}{37.5 \text{ m}^2}
σ
=
A
N
=
37.5
m
2
4
kN/m
2
×
37.5
m
2
×
7.5
m
=
24
×
7.5
kN/m
2
=24 \times 7.5 \text{ kN/m}^2
=
24
×
7.5
kN/m
2
⇒
FOS
=
(
c
+
σ
tan
φ
)
A
P
\Rightarrow \quad \text{FOS} = \frac{(c+\sigma \tan \varphi) A}{P}
⇒
FOS
=
P
(
c
+
σ
t
a
n
φ
)
A
=
(
17
+
24
×
7.5
×
tan
2
5
∘
)
×
37.5
1875
= \frac{(17+24 \times 7.5 \times \tan 25^{\circ}) \times 37.5}{1875}
=
1875
(
17
+
24
×
7.5
×
t
a
n
2
5
∘
)
×
37.5
FOS
=
2.0187
\text{FOS}=2.0187
FOS
=
2.0187
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