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GATE Civil Engineering (CE) 2020 Shift 1 Solved Paper
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© examsnet.com
Question : 37 of 65
Marks:
+1
,
-0
A rigid, uniform, weightless, horizontal bar is connected to three vertical members
P
f
Q
P_{f} Q
P
f
Q
and
R
R
R
as shown in the figure (not drawn to the scale). All three members have identical axial stiffness of
10
k
N
/
m
m
10\,\mathrm{kN}/\mathrm{mm}
10
kN
/
mm
. The lower ends of bar
P
P
P
and
R
R
R
rest on a rigid horizontal surface. When NO load is applied, a gap of
2
m
m
2\,\mathrm{mm}
2
mm
exists between the lower end of the bar
Q
Q
Q
and the rigid horizontal surface. When a vertical load
W
W
W
is placed on the horizontal bar in the downward direction, the bar still remains horizontal and gets displaced by
5
m
m
5\,\mathrm{mm}
5
mm
in the vertically downward direction.
The magnitude of the load W (in kN, round off to the nearest integer), is
Your Answer:
Validate
Solution:
A
E
L
=
10
k
N
/
m
m
\;\frac{AE}{L}=10\,\mathrm{kN}/\mathrm{mm}
L
A
E
=
10
kN
/
mm
w
1
+
w
2
+
w
3
=
W
w_{1}+w_{2}+w_{3}=W
w
1
+
w
2
+
w
3
=
W
from symmetry
⇒
w
1
=
w
3
\Rightarrow w_{1}=w_{3}
⇒
w
1
=
w
3
δ
p
=
5
m
m
=
w
1
L
A
E
\delta_{p}=5\,\mathrm{mm}=\;\frac{w_{1} L}{A E}
δ
p
=
5
mm
=
A
E
w
1
L
∴
W
1
=
50
k
N
=
w
3
\therefore W_{1}=50\,\mathrm{kN}=w_{3}
∴
W
1
=
50
kN
=
w
3
δ
Q
=
w
2
L
A
E
\delta_{Q}=\;\frac{w_{2} L}{A E}
δ
Q
=
A
E
w
2
L
∴
w
2
=
30
k
N
\therefore w_{2}=30\,\mathrm{kN}
∴
w
2
=
30
kN
∴
W
=
130
k
N
\therefore W=130\,\mathrm{kN}
∴
W
=
130
kN
© examsnet.com
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